X^2-3x-18/x-6

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Solution for X^2-3x-18/x-6 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

X^2-(3*x)-(18/x)-6 = 0

X^2-3*x-18*x^-1-6 = 0

-3*x^1-18*x^-1-6*x^0 = 0

(-3*x^2-6*x^1-18*x^0)/(x^1) = 0 // * x^2

x^1*(-3*x^2-6*x^1-18*x^0) = 0

x^1

-3*x^2-6*x-18 = 0

-3*x^2-6*x-18 = 0

DELTA = (-6)^2-(-18*(-3)*4)

DELTA = -180

DELTA < 0

x in { } 

x belongs to the empty set

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